Question

how can you find the polar coordinates of (-2, 5) & satisfy 0≤theta≤2pi and -pi ≤theta≤pi ?

Answer 1

r=sqrt(2^2+5^2)=sqrt(29)
theta=tan^-1(5/-2)

x=r cos theta,
y= r sin theta

Answer 2

theta=292 for first case and
theta=-68 ..........2 nd case

Answer 3

oh! got it!

Answer 4

in polar co -ordinates we wrie the points as (r, theta)
for first case (sqrt(29), 292)
for 2nd case (sqrt(29),-68)