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Write the quotient in the form a+bi 1+3i over 5+3i
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\[\frac{1+3i}{5+3i}=\frac{1+3i}{5+3i}\times \frac{5-3i}{5-3i}\]
denomimator is \[25+9=33\]
numerator is \[5+9+(-3+15)i=14+12i\]
giving an answer of \[\frac{14+12i}{33}=\frac{14}{33}+\frac{12}{33}i\] in standard form
a little short on the denominator.
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oops!
\[25+9=...\]
addition never my strong suit !
Hi satellite73
hi radar! thanks for catching my mistake! i guess answer is actually \[\frac{14}{34}+\frac{12}{34}i=\frac{7}{17}+\frac{6}{17}i\] unless i made another mistake
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