Give the definition of the modulus function R -> R, often denoted by x -> |x|. (This is also called the absolute value function.) Draw the graph of the function R -> R defined by x -> ||x - 1| -2|. Express {x e R ||x-2| < 3g as} an open interval (a; b) for suitable a; b e R.
cheers guys, any ideas how to do the last part?
is the graph clear? because i can send it step by step
\[|x-1|\]
\[|x-1|-2\]
thanks for that, i get it.
any ideas for last part?
\[||x-1|-2|\]
i don't really understand what the last one says. are you supposed to write this as a piecewise function?
it says "express \[|x-2|<3g\] as an open interval?
i am confused by the question. if that is what it is asking, then i think the answer is easy. if g = 0 you get x = 2 if g < 0 no answer if g > 0 you solve \[|x-2|<3g\] \[-3g<x-2<3g\] \[2-3g<x<2+3g\] so open interval is \[(2-3g,2+3g)\]
yes, sorry
ok then that is the answer above.
thanks very much, i get it now. appreciate it
yw
Join our real-time social learning platform and learn together with your friends!