looking to find the differential (dy) when (x=1) and (dx=0.1) for the equation y=4x^2=3x=3
Step by step would be great?

Question

looking to find the differential (dy) when (x=1) and (dx=0.1) for the equation y=4x^2=3x=3 
Step by step would be great?

anonymous · Answer

$$y=4x^2+3x+3$$?

amistre64 · Answer

$$\int dy = (4\int (x^2)dx)+(3\int(x)dx)+(3\int dx)$$

anonymous · Answer

$$y = 4x ^{2}+3x+3$$
to find y' the derivative can be spread among the different additive portions
then using the Power rule on each variable you find 
$$y' = (4x^2)'+(3x)'+3$$
$$y' = (4*2)x+(3*1)+0$$

where the derivative of a constant = 0

anonymous · Answer

confused by the equal signs. guru?

amistre64 · Answer

nah master, its a common typo on my end too lol

anonymous · Answer

i think that is wrong. you are just looking for the differential yes?

anonymous · Answer

amistre64 the question is only asking for the derivative, not the integral ;-)

amistre64 · Answer

lol ..... well, when the question to my answer comes around; just point them to it ;)

amistre64 · Answer

diffrential; differential equations; ... they really should come up with more words to use for this stuff ;)