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Mathematics 10 Online
OpenStudy (anonymous):

calculus anyone?

OpenStudy (anonymous):

Yes.

OpenStudy (anonymous):

yes with cream please

OpenStudy (anonymous):

sorry - silly joke!

OpenStudy (anonymous):

haha I have an exam and im LOST

OpenStudy (anonymous):

Where to begin?

OpenStudy (anonymous):

its basic for u guys probably derivatives

OpenStudy (anonymous):

Do you understand the definition of a derivative?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

or are you having trouble with the rules on how to take the derivative

OpenStudy (anonymous):

k like this question, commute f(c+h)-f(c) at indicated points f(x)=-2+1; c=2

OpenStudy (anonymous):

sorry im slow at typing this stuff

OpenStudy (anonymous):

its fine:) ok so that is the definition of a derivative, f(c+h) means replace 'x' with 'c+h' in the equation, and f(c) means replace 'x' with 'c' in the equation. Ignore c=2 for the moment

OpenStudy (anonymous):

and this website is a little tricky to figure out:P

OpenStudy (anonymous):

hmmm k?

OpenStudy (anonymous):

is there suppose to be an x in the equation f(x) = -2+1 ?

OpenStudy (anonymous):

oops yes, -2x+1

OpenStudy (anonymous):

ok. taking f(c+h) - f(c) = [-2(c+h)+1] - [-2(c)+1]

OpenStudy (anonymous):

why [-2(c)+1]

OpenStudy (anonymous):

because its f(c+h) - "f(c)" and f(c) = -2(c)+1

OpenStudy (anonymous):

k

OpenStudy (anonymous):

if i remember the formula correctly i believe we are to take \[\lim_{h \rightarrow 0} [f(c+h)-f(c)]/h\]

OpenStudy (anonymous):

k? lol im so lost

OpenStudy (anonymous):

is that the quotient rule

OpenStudy (anonymous):

here let me send you to an online area that explains this better. then after reading that section come back and ask any other question you have that wasn't answered: http://tutorial.math.lamar.edu/Classes/CalcI/DefnOfDerivative.aspx

OpenStudy (anonymous):

thnx:)

OpenStudy (anonymous):

u just starting calculus shenys?

OpenStudy (anonymous):

it can be difficult at first but once you grasp the concepts it is not so hard and is quite interesting

OpenStudy (anonymous):

yes:(

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