Question

Find all values of θ in the interval 0° ≤ θ < 360° that satisfy the equation sin 2θ = sin θ. i know the answer just want to know how i do it thanks

Answer 1

you need to rewrite
\[\sin(2x)=2sin(x)cos(x)\]

Answer 2

sin 2A = 2sinA cosA
so 2sinAcosA=sinA
2cosA=1
cos A =1/2
fins all values of A that satisfy cos A =1/2

Answer 3

i think its sin ^2 theta

Answer 4

then go from there
\[2sin(x)cos(x)-sin(x)=0\]
\[sin(x)(2cos(x)-1)=0\]
\[sin(x)=0\] or
\[cos(x)=\frac{1}{2}\]

Answer 5

first one gives x = 0
second one give x = 60 or x = 300

Answer 6

since you are working in degrees

Answer 7

2 sinθ cosθ n - sinθ = 0
sinθ (2 cosθ - 1)
= 0
θ = 0, 180, 60, 300

Answer 8

jimmyrep is right. i forgot that 180 works for sin(x)=0 as well. he is correct

Answer 9

I still dont get it but thanks for trying i probably just need it spoken step by step ill ask tomorrow :]