Question

can someone please help me??

Identify the equation of a circle that has a diameter with the end points (6,-8) (10,4)

Answer 1

A- (x-8)^2 + (y+2)^2 =40
B- (x+8)^2 + (y+2)^2 = 40
c- (x-8)^2 + (y-2)^2 = 40

Answer 2

Since the circle's diameter is defined by the segment between the points (6,-8) and (10,4) , then it's center is on the center of this segment.

The X-coordinate of the circle's center is in the middle between 6 and 10 = 8.
The y-coordinate of the circle's center is in the middle between -8 and 4 = -2

So the equation of the circle is:
(x - 8)^2 + (y - (-2)) ^2 = 40
(x-8)^2+(y+2)^2=40 ----> Answer A