Question

Rewrite the expression

log5 (2√(x +1)3 / 3√3x + 7) in a form with no logarithms of products, quotients, or powers.

Answer 1

\[\log base 5(2\sqrt{(x+1)_{}^{3}} / \sqrt[3]{3x+7})\]

Answer 2

\[\log_5({2\sqrt{(x+1)^3} \over 3\sqrt{3x+7}})\] Is this the expression?

Answer 3

Yes, that's it :)

Answer 4

The second one is \[^{\sqrt[3]{3x +7}}\]

Answer 5

OMG I didn't say that! Just a minute, I have to do it again.

Answer 6

It's okay, i will wait a while :)

Answer 7

So is the numerator \[\sqrt[2]{(x+1)^3}?\]

Answer 8

\[ 2\sqrt{(x+1)^{3}} \over \sqrt[3]{3x+7}\]

Answer 9

better?

Answer 10

with the \[\log _{5}\] infront

Answer 11

Good, that's much better :D
\[\log_5{2\sqrt{(x+1)^3} \over \sqrt[3]{3x+7}}=\log_5(2)+\log_5(x+1)^{3 \over 2}-\log_5(3x+7)^{1 \over 3}\]
\[=\log_5(2)+{3 \over 2}\log_5(x+1)-{1 \over 3}\log_5(3x+7)\]

Answer 12

Ah..thank you so much, I really appreciate it!!!I get more help online than in my own country...You are a life-saver! :)