Question

if an equation has only an x^2 term how would you solve give an example

Answer 1

For ax^2+bx+c=0
x = \[(-b \pm \sqrt{b^{2}-4ac}) \over (2a) \]

Answer 2

So for
x^2 =0
x =\[ -0 \pm \sqrt{0^{2}-4*1*0} \over 2*1 \]
=0 or 0

Answer 3

It's useful to get in the habit of using this method however all you really need to do is square root what x-squared equals but the first method works when you have x terms as well

Answer 4

so what do i write as my answer she wants a complete sentance

Answer 5

To solve an equation that only has an x^2 term rewrite the equation so you have x^2 on one side of the equation then square root the other side remembering to give the positive and negative root.

Answer 6

eg
\[x^2 -9=0\]
\[x^2=9\]
\[x= \pm 3 \]