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z^4+10z^2+9
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make the substitution t = z^2 so the equation becomes \[t^2+10t+9\] then factorise it.
once finished replace t with z^2. do you see?
t^2 + 9t + 1t + 9 t(t + 9) +1(t + 9) (t + 1) (t + 9) now put t = z^2, we get (z^2 + 1) (z^2 + 9)
When you factorise you look for factors of 9 that when added give you 10; so htats +1 and +9 so the factorisation is (t+1)(t+9) now do a straight substitution: t for z^2 that gives \[(z^2+1)(x^2+9)\] as an answer as above.
ha I types x in the second bracket. So used to typing x. make it a z,lol
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