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square root of 36x=x+8
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hello the same process as the other ex. \[\sqrt{36x}=x+8\] square both sides 36x=\[\left( x+8 \right)^{?}\]
\[6\sqrt{x}=x+8\] \[36x=x^2+16x+64\] \[x^2-20x+64=0\] \[(x-4)(x-16)=0\] \[x=4\] or \[x=16\]
x= 4, 16 square each side to get rid of sqrt first
and of course once again you have to check
\[\pm \sqrt{36x}=x+8\] \[36x=x^2+16x+64\]
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^^^ ya satellites got it
ok now its just a repeat of the above you guys beat me to it :D
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