Question

simplify:(2x^2y^-1)^3??????

Answer 1

don't understand the format

Answer 2

(2xsquared2y to the neg. 1) cubed

Answer 3

its with exponents

Answer 4

(8x^58y^-1) I believe

Answer 5

how?

Answer 6

The whole thing is cubed so you multiply each number 3 times

Answer 7

Not times 3 though

Answer 8

how did you get the 8y?

Answer 9

i understand that 8x b/c 2cubed is 8

Answer 10

2x2=4.... 4x2=8 (That is 2 cubed)

Answer 11

yes I know but im talking about the 2nd 8

Answer 12

You said it was 2y^-1

Answer 13

the 2 was ment for the x squared

Answer 14

Oh okay. So it would be (8x^5y^1)

Answer 15

lol ok now that makes sense thanks!

Answer 16

No problem :)

Answer 17

I think you mean \[(2x ^{2}y^{-1})^{3}\]
You would apply the cube to all parts inside the parentheses
\[2^{3}(x^{2})^{3}(y^{-1})^{3}=8x^{6}y^{-3}\]

Answer 18

yes excatly! how did u type that in??

Answer 19

Use the equation editor button below the text box

Answer 20

btw, the answer lexlovesyouu gave is incorrect. \[(x^{2})^{3}\] does not equal \[x^{5}\]
\[x^{5} = x^{2}x^{3}\]

Answer 21

Good way to remember when to add and when to multiply exponents is to count the variable. For instance:
\[x^{2}x^{3}\] has two x's then three x's for a total of 5 x's
\[(x^{2})^{3}=x^{2}x^{2}x^{2}\]
has two x's then two x's thentwo x's for a total of six x's

Answer 22

\[8x ^{3/2y}\]