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can someone simplify log2^12 - log2^6 ???
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apply quotient law log 2^12/6 log 2^2= 1
yes the difference of two logs with the same base can be regrouped into a single log of a quotient
\[\log(2^{12})-\log(2^6) \rightarrow \log \frac{2^{12}}{2^6}\]
well the answer is 1
because u arrive at log2^2, and the inverse property loga^a^x suggests that the answer is 1
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I confused \[\log(2^{12})-\log(2^6) <> 1\] it equals 1.806!
the answer should be \[\log(2^6)=1.806\]
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