Question

find the mean, variance, and standard deviation of the binomial distribution with the given values of n = 127, p = 0.63

Answer 1

the mean is simply n*p

the variance is n*p*(1-p)

and the sd is the sqrt(variance)

Answer 2

I get:
mean = 80.1
variance = 29.6037
sd = 5.441

Answer 3

IM SORRY THE P = 0.39

Answer 4

AND THE N= 129

Answer 5

in that case, just adjust for the error :)

129(.39) = mean

129(.39)(1-.39) = variance

\(\sqrt{129(.39)(1-.39)}\) = standard deviation

Answer 6

SO I NEED TO ROUND TO THE NEAREST TENTH AS FOR ALL 3 STEPS

Answer 7

5O.31 ROUND TO THE NEAREST TENTH