Is it possible to graph the equation y = -(6/7)x + 6?
yes 6x+7y=42
without it going below the x axis, I should add..
i dunno, that might be one of those not doable lines ....
anything with a slope other than zero will go below the x axis at some point
It involves a story problem though...so I don't think 'no solution' is a choice...
Did you re-write it in the y= mx + b form? It has a portion of the line in the +/+ region.
I rewrote 6x + 7y = 42 as y = -(6/7)x + 6..
Indeed. So the y intercept is?
y intercept is 6...but the negative 6 over 7 is throwing me off, as far as graphing the line..
Any line can be extended in either direction. So, line has to go below X axis
It's ok. so that means you will go down 6 and over 7.
So there's still quite a bit of area above the x axis.
So I just draw the one point directly on the x axis...and draw the line between the two points?
Yep.
If you have problem graphing slope-intercept form, convert it into standard form Ax+By=C. It is easier to graph
the one involving the negative 6 over 7, that is..
ok, then...
You have the point (0,6) and (7,0)
A Mathematica plot is attached.
and all the points on the line between them.
ok then...thanks a lot guys...it helps me to discuss out my math problems..
of course!
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