Find an identity for cos5x in terms of cosx.
cos(x+x+x+x+x) :)
I don't think that's what they had in mind. lol
:) start with cos(x + 4x) and turn it into: cos(x)sin(4x) - cos(4x)sin(x) and work it all down to from there, if i see it right; but that is a pain
I've tried that and several other attempts. Perhaps its just because I hate arithmetic. the text has16cosx^5 - 20cosx^3 +5cosx
cos(x)sin(4x) - cos(4x)sin(x) cos(x)[sin(x)sin(3x) + cos(x)cos(3x)] - [cos(x)cos(3x)-sin(x)sin(3x)]sin(x) cos(x) - sin(x) sin(x)sin(3x) + cos(x)cos(3x) cos(x)cos(3x)-sin(x)sin(3x) ........................................................... cos(x) sin(x) +cos(x) sin(x)sin(2x) + cos(x)cos(2x) cos(x)cos(2x) - sin(x)sin(2x) - sin(x) cos(x) -sin(x) cos(x)cos(2x) - sin(x)sin(2x) sin(x)sin(2x) + cos(x)cos(2x) ............................................................... yeah, its a pain :)
Can you use the triple and double angle formulas to break it up? I started, but my brain is hurting. Split it into cos(3x + 2x) = cos(3x)cos(2x) - sin(3x)sin(2x). I worked the first term using cos(3x)=cos^3(x) - 3sin^2(x)cos(x) and cos(2x)=cos^2(x)-sin^2(x) and got 8cos^5(x)-7cos^3(x)+3cos(x). Haven't worked the second term though...but it looks promising, no?
It does. I haven't come up with coefficients that look that hopeful in many attempts
\[Cos[5 x] = 5 Cos[x] - 20 Cos[x]^3 + 16 Cos[x]^5 \]
Ok...my algebra is, I'm sure off, but for me it reduced to -8cos^5x - 12cos^3x +cosx which is not what your book says. But I think the idea is sound...but my algebra is wonky.
Got it!
whew!
beautiful. thanks to both of you.
no problem. that was an outstanding refresher for me. it took putting down the pen and typing it out to keep my terms in place. :)
A Mathematica solution with comments is attached.
could you try again. All I got was a black box off screen. Thanks.
This site does't allow tiff files to be attached. I'll have to covert a tiff screen capture to jpg.
I'd appreciate it. I'll give you a medal in advance.
Thanks for the medal. A jpg is attached. Sorry for the delay. Had to bring up a virtualized version of Ubuntu Linux and then use the Terminal command, Convert.
There was an error in the last comment. Equate Cos[x]^5 to .... should have been typed, Equate Cos[5x] to ... Correct pdf version is attached.
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