Question

I am back! I am stuck on the same problem, but at least I am further along:)

Answer 1

\[x=+4\pm \sqrt{16+8} all of this is divided by 2\]

Answer 2

What is 16 + 8?

Answer 3

See, that is what we were unsure of; do we add or take the square root of both numbers?

Answer 4

For instance, would it be 24 or do you take the square root of the 16 and the 8?

Answer 5

You have to add first, then take the square root.

\[\sqrt{a + b} \ne \sqrt{a} + \sqrt{b}\]

Answer 6

But then you have to break it down again? What do you do with the number outside?

Answer 7

Well what is \(\sqrt{24}\)

Answer 8

4*6

Answer 9

Or 2\[\sqrt{6}\]

Answer 10

Right. \(2\sqrt{6}\).

So you have:
\[{4 \pm 2\sqrt{6} \over 2}\]

Answer 11

Ok, can you then reduce it down?

Answer 12

Of course. You can divide each of the terms by 2.

\[{4 \pm 2\sqrt{6} \over 2} = {4 \over 2} \pm {2\sqrt{6} \over 2} = 2 \pm \sqrt{6}\]

Answer 13

Yea, we got that far:) the problem we have is getting it into decimal form.

Answer 14

Why bother?

Answer 15

Oh, we just figured it out! Thank you thank you thank you!!

Answer 16

I mean if you want you can just figure out what the decimal form of \(\sqrt{6} \) is then add and subtract that from 2 and you have your two solutions.. But the original way looks lots neater.

Answer 17

Most certainly. The answer according to the professor is in decimal form which is why we were wondering. Thank you thank yyou thank you!! We just figured it out!

Answer 18

Nicely done! =)

Answer 19

YOu are great! Thank you so much! GOD bless<><

Answer 20

I'm technically Buddhist, but thanks anway ;)

Answer 21

Well thank you, GOD blessed us through you.

Answer 22

Fair enough =)

Answer 23

God loves and appreciates you as do we:)

Answer 24

Happy to help.