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If a < b and c > d, prove a - c > b - d
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sorry, it should be prove a - c < b - d
a<b d<c a+d<b+d<b+c a+d<b+c a+(-c)+d<b+c+(-c) a+(-c)+d<b a+(-c)+d+(-d)<b+(-d) a-c<b-d
hmmm looks okay
I think we need to know that a, b and c are each positive, otherwise things might go wrong. How about a<b, so a-c<b-c<b-d, because c>d?
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