If a is rational and b is irrational, is ab necessarily irrational? (Careful!)
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myininaya (myininaya):
we need a contradiction
OpenStudy (anonymous):
may be, not really
OpenStudy (anonymous):
u can use that in one case
myininaya (myininaya):
b=baa^(-1) is irrational
b=aba^(-1)=(ab)(a^(-1))
a is rational => a^(-1) is rational (assuming a doesn't =0)
but for b to be irrational that means ab has to be irrational
OpenStudy (nikita2):
if a = 0 then ab is rational. Assume a not= 0 and ab is rational then ab/a is rational too, so b = ab/a has to be rational.
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myininaya (myininaya):
but 0 is rational
0*b is rational
OpenStudy (anonymous):
hey nikita do u have this book? ny Michael Spivak?
OpenStudy (anonymous):
by*
OpenStudy (nikita2):
definitely no )
OpenStudy (anonymous):
okay ur approach is right
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