Hi, I'm having a bit of trouble finding the integral for 1/(1+x^7) and e^(-x^2) could someone point me in the right direction please?
try wolframalpha.com it shows steps too
not for these two, the steps are unavailable. If you can see the procedures to take let me know
e^(-x^2) isnt this the same as e^(-2x) ?
it aint :)
I don't think so,
there are plenty of functions that are simply not integrateable
true, so do you see any integration technique available to a Calculus 2 student that would solve these 2 equations?
i got books in the library here with tables of integration ... much more extensive than the leaflets in the textbook
would it not be ln[1+x^7]+C?
take the derivative to test it out :)
there is a 7x^6 missing for that to be good; maybe try int by parts?
or fancy substitutions ;)
hmm, ok, ill see about those
suppose we make: x = z^(1/7)
dx = (z^6)/7 dz \[\int\frac{1}{1+(x)^7}dx\] \[\int\frac{z^6}{7(1+(z^{1/7})^7)}dz\]
i messed up the derivative of z^(1/7) i think :)
-6/7
im gonna switch to another variable that stands out better \[[a^{1/7}]'=\frac{1}{7a^{6/7}}\] \[dx = \frac{1}{7a^{6/7}}dz\]
\[\int\frac{1}{7a^{6/7}(1+a)}da\] is that workable?
I think we could int by parts now
I don't know, I've never done sometihng like this but I have a=7a^6/7, could this lead to an answer?
cant really say fer sure. Ive never tried it out b4 either :) still leafing thru some pages tho
I think the questions are bogus, e^(-x/2) involves an error function which we havent learned yet, and the answer for 1/(1+x^7) is humongus
in other words, I think we are supposed to realize that these are unsolvable for us
thx for the help :)
yep; that right :) my text says: "you should realize that no table is adequate for all integration problems. A simple example is \(\int\ e^{-x^2}\). No elementary function exists whose derivative is \(e^{-x^2}\); in such a case it is necessary to restort to approx. techniques.
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