derivative of root 3 will be 0, right?

Question

anonymous · Answer

ys

anonymous · Answer

then solve this: 
$$(x ^{3}\div \sqrt{3}) - \sqrt{3}x ^{3}$$

amistre64 · Answer

root 3 is a constant; so yes ;)

anonymous · Answer

then differentiate the above equation for me, please? because that's what I am doing and the answer doesn't seem to match. will be apply the quotient or product rule? or just differentiate it directly?

bahrom7893 · Answer

x^3/sqrt(3) - sqrt(3) * x^3, the derivative is:
3x^2/sqrt(3) - 3sqrt(3)*x^2

amistre64 · Answer

$$Dx[\frac{x^3}{\sqrt{3}}-\sqrt{3}x^3]=Dx[\frac{x^3}{\sqrt{3}}]-Dx[\sqrt{3}x^3]$$

amistre64 · Answer

$$\frac{3x^2}{\sqrt{3}}-3\sqrt{3}x^2$$
is what I get from it

amistre64 · Answer

its just the power rule applied after pulling out the constants; then multiply the constants back in

anonymous · Answer

what about the first term? shouldn't we not apply the quotient rule?

amistre64 · Answer

$\frac{1}{\sqrt{3}}x^3$ doesnt require the quotient rule any more than any other constant; since the variable is not a part of the bottom

amistre64 · Answer

the end result, if I see it right is:  -2 sqrt(3) x^2

amistre64 · Answer

if you wanna DO the quotient rule; it works out the same:

$$\frac{3\sqrt{3}\ x^2-0(x^3)}{3}$$

anonymous · Answer

oh okay, thanks a lot :)

amistre64 · Answer

youre welcome :)