Question

find the equation of the tangent line to the curve

y= secx at coordinates(pi/3,1)

Answer 1

dy/dx at the given point.

Answer 2

thats the slope.

Answer 3

y'=secxtanx

=secpi/3*tanpi/3
m=2*sqrt{3}

y-1=2sqrt3(x-pi/3)

how do i simplify that?

Answer 4

i know how to do it its just simplifying it at that point

Answer 5

thats it. you don't need to simplify it further.

Answer 6

the problem asks for the equation of the tangent. you have already worked out the equation. there is no need to simplify it.

Answer 7

okay thank you