A group of ten women and twelve men must select a three person committee. How many committees of one woman and two men are possible? --- This is a counting method and probability problem.

Question

anonymous · Answer

10 * 12C2 = 10 * (12*11/2)= 10 * 66 = 660

anonymous · Answer

seems a heck of a lot !!

anonymous · Answer

but i think its correct as there any of  ten women combuned  with the possible combinations of two from 12 men

anonymous · Answer

why you divided 11 by 2 ?

anonymous · Answer

Think about it

anonymous · Answer

i  multiplied 12 by 11 to give 32 then divided by = 132 / 2 = 66

anonymous · Answer

i think the cmbinations of two man are just 132 = 12*11

anonymous · Answer

ok ok forget it

anonymous · Answer

Yeah I think @AlleluiaSB is correct on this one. Thank you both.

anonymous · Answer

the formula  for combinations of r from n items =
n! / (n-r)! r!
which is the same thing as for example  2 combinations in 4 =
4*3 / 2*1

anonymous · Answer

12*11 = number of permutations not combinations  - in permutations the order is important in combinations it is not

anonymous · Answer

Oh ok

anonymous · Answer

in my calculations some groups had the same couple of man. sorry about it.

anonymous · Answer

for example take a b and c 
permutations of 2  are ab ac bc ba ca cb
combinations are ab ac bc  - the order does not matter

anonymous · Answer

yep - no probs

anonymous · Answer

what does 10 * 12C2 mean?