Question

Evaluate the definite integrals

[tex]\int_{{0}_{1}}{\frac{dr}{((7-5r)^{2})^{1/3}}}[/tex]

Answer 1

looks horrid this way :)

Answer 2

ok this looks like gibberish one sec

Answer 3

\[\int\limits_{0}^{1}\frac{dr}{(7-5r)^\frac{2}{3}}\]

Answer 4

This is easier than the last one

Answer 5

let u=7-5r
du=-5 dr
-1/5 du=dr
if x=1, then u=7-5(1)=2
if x=0, then u=7-5(0)=7

Answer 6

myininaya dont write the solution, please. Purplec should be able to solve this, we can help if he is stuck.
I was too slow :DDD

Answer 7

ok andras

Answer 8

do you know where you got stuck with this?

Answer 9

well the solution is there now, I hope it is clear.
For many integrals substitution is a good solution. The only thing you have to be carefull how the dx changes to du

Answer 10

omg...would you believe all that time i was fighting to put in in the post and it delted!!! :@

Answer 11

:)

Answer 12

myinaya put in right but i forgot about my algerba that i cant raise it 2/3

Answer 13

and yes it is easier lol

Answer 14

integration by parts is the other tool that you have to use a lot

Answer 15

for example for integral x^2 * sinx

Answer 16

i am not a he i am a she thank you very much...why would a guycall himself purple lol? newho

Answer 17

okok :) I am a guy and I do like purple

Answer 18

also partial fractions is good tool to integrate