33l^2-l^3-33l Find the zeros of this polynomial function.
Don't you want to maximize the volume?
Would I be able to use the quadratic formula?
No quadratics only work with powers of 2. There are cubic formulas, but they take up alot of room. You could use calculus! lol. The maximum volume is 4.61*10^3 at l=21.5cm. the zeros are: 0 and 32.
Hm. O.k thank you for the helpful explanation! How about this: Write an inequality that describes the possible values of x for our box problem. Remember that the y value is the volume, and that none of the dimensions can be 0 or negative.
(This maybe referring back to my other scenerio.)
3<x<30. h=3-x, so if x is 3 or less, h is zero or negative. w=30-h, so if h is 30 or more, w is zero or negative.
Volume is positive across all of those values too. You'll have to trust my TI-Nspire CAS for that though.
Thank you! I don't have the proper calculator handy :/ Do you mind? Use your calculator to find the value of x that gives the maximum volume. Use 2nd TRACE (CALC) and choose the maximum command. Round your answer to the nearest tenth.
1) TI-Nspires don't work using those exact commands. 2) The maximum is posted in my second post. 3) Because I'm lazy too: V=4.61*10^3 cubic cm at x=21.5cm
Also, I'm sorry about the too part, it was not meant to insult you in any way.
Oh lol :) No it's fine! I am! :) Thank you for the help kd8cpk!
mathsux4real, What is that symbol that looks like a vertical bar? Is it a lower case L?
Oh yeah... lowercase L=l
A Mathematica solution with comments is attached.
Wow THANKS
The numeric value of the roots are:\[\{\{x\to 0.\},\{x\to 1.03229\},\{x\to 31.9677\}\} \]
Thanks :)
Your welcome.
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