Question

please help me out in this ... integrate this equation sin^4(e^2x)cos(e^2x)e^2xdx. thanks

Answer 1

use substitution
u=e^2x
du=2e^2xdx
1/2du=e^2xdx

U will get
1/2 sin^4(u)cos^4(u) du
1/2 (sinucosu)^4
1//2(1/2sin2u)^4
1/32(sin2u)^4

Answer 2

is it clear until this?

Answer 3

thank you so much...

Answer 4

can i ask again?? bout the integration of e^4u du/(1+3e^4u)^2

Answer 5

use substitution w=1+3e^4u
than dw=12e^4u du
1/12dw=e^4udu

Answer 6

so it will be
1/12 1/w^2 dw
integrate to get -1/12w

Answer 7

and plug w=1+3e^4u back into this

Answer 8

i get it thanks.