Question

what is it series for the following x=1 , 2 , 4 , 64 --- and so on

Answer 1

what is 'what'?

Answer 2

x(sub n) = 2^(n-1) is the best that I have. It isn't right for the set you wrote, but are you sure it isn't 1,2,4,...,64?

Answer 3

the sequence might be:

A{n} = 1 + A{n-1}^ .... thats where my confusion is too lol

Answer 4

2^2 = 4
4^3 = 64
5^4 = ...
6^5 = ...

Answer 5

only thing is... 1^2 = 1 :)

Answer 6

1^1
2^2
4^3
8^4?

Answer 7

ack

64^4 = ....
...^5 = ....
... ^6 maybe?

Answer 8

which is A{n}=(2^(n-1))^n

Answer 9

OR A{n}=2^(n^2-n)

Answer 10

Final answer

Answer 11

i think thats the best we can do without knowing what the problem is asking for to begin with :)

Answer 12

2^0, 2^1, 2^2, 2^6 best I can do is 2^16 (16 is twice the sum of the previous 2 exponents) the question lacks definition.