Question

how do you graph an ellipse in y= form in parametric with a calculator

Answer 1

x= a cos[t]
y= b sin[t]

Answer 2

but when you make a program it has to be in a y= form

Answer 3

not in parametrics but using an equation of parametrics

Answer 4

a program doesnt have to be in y=... format; you can simply define the point by parametrically

Answer 5

if your looking to do it on a ti83 perhps?

Answer 6

like i need to explain the program
:for(z,0,180,360,5)
:pt-on(sin(z)+32,Cos(z)+32)
yes

Answer 7

since an ellipse is not a 'function' it has to be split into 2 parts; upper and lower

Answer 8

*for(z,0,360,5)

Answer 9

so cos is graphing the lower part and sin is graphing the upper part of the ellipse

Answer 10

y = +sqrt( a cos(t)^2 + b sin(t)^2) for the top part
y = -sqrt( a cos(t)^2 + b sin(t)^2) for the bottom part, i think

Answer 11

hold on i'll try it

Answer 12

i got an argument error, but my teacher told me it was y=a sin(z)+C
y=b cos(z)+D

Answer 13

but to explain the math of the equation like conversion from rectangular to parametric

Answer 14

parametrics simply define x and y in their own rights; and usually they are linked by time.

To combine them, takes a good eye, but one strategy is to solve for t in terms of x and insert that into y

Answer 15

alright could you give me a conversion from rectangular to parametric of any equation just so i know how to do it though

Answer 16

rectangular and parametric play in the same ballpark; they arent like moving from polar to cartesian ... IF y can be defined as a function of x, the best way to do it is by knowing a few basics and testing;

r^2 = x^2 + y^2
x = r cos(t)
y = r sin(t)

thats about it; the rest is seeing how to define 't' in terms of x so that you can sub it into the equation for y

Answer 17

alright thnx good answer

Answer 18

try this one out:

y = a sin(cos-1(x/b))
y = -a sin(cos-1(x/b))

my ti83 makes an ellipse out of it

Answer 19

i got an argument error but i have to put mine in a program so it might be different well thats why i'm getting errors

Answer 20

I cant recall to much of my programming way back when; but I do alot of javascripting; and it would look like this:

y = a*Math.sin(Math.acos(x/b))

not sure if thats helpful; but its the closest I can get :)

Answer 21

alright i'll try to change what i have to make it work but thnx for the conversion i might be able to work off that to figure it out

Answer 22

this is what I get :)