Question

the formula of a projectile flying through the air is vsin(theta) and v cos(theta) give me an explanation in how this works

Answer 1

why does this cause a object to fly through the air

Answer 2

this is the expression of velocity

Answer 3

yes i just need a brief explanation in why this works

Answer 4

if u see any projectile with velocity v launched at an angle t to the horizontal..
u can split its velocity as a vector

Answer 5

wtdu mean this causes an object to fly?

Answer 6

well i'm making a calculator program and we have to make an object fly and he gave us this formula and it works so now he wants math behind it idk

Answer 7

v(x) = vcost v(y) = vsint
a(x) = 0, a(y)=g

Answer 8

whats a(x)=0 and a(y)=g

Answer 9

a(x) is acceleration along x axis

Answer 10

a(y) is accn along y-axis which is g= 9.8 m/s^2

Answer 11

how does this come into play

Answer 12

x = vcos(theta) . t
y = vsin(theta).t - 0.5 gt^2

Answer 13

u know wht a parabola is?

Answer 14

yeah

Answer 15

now t is the parameter here, eliminate it

Answer 16

so divide t and get x/t=v cos(theta) and y/t=v sin(theta)-.5gt^2

Answer 17

find the val of t frm the first eqn and put it into the 2nd

Answer 18

ull get a parabola

Answer 19

\[y = xtan{\theta} - gx^{2}/2u^{2}\cos^{2}{\theta}\]

Answer 20

isnt this a parabola?

Answer 21

is it or is it not?

Answer 22

Helpful illustration:
http://en.wikipedia.org/wiki/File:Dot_Product.svg


Sin of an angle gives you the vertical component of the vector.
Cos of an angle gives you the horiontal component of the vector.
The notation |A| means "the length of the vector A".