Question

If f(x)=sum of (X^n)/(n!) for n=0 to infinity for all x, then f^(4)(0)=4! how do I figure this out?

Answer 1

figure what out?

Answer 2

if the answer is 4!

Answer 3

if it's helps:
lim (n->infinity)x^n/n! = 0 for every real number x

Answer 4

not really but thanks, I'm reading through here, and it has to do with taylor series

Answer 5

would it not be 1?

Answer 6

f(x)=e^x
f'(x)=e^x
...
f''''(0)=e^0=1
thats what i think

Answer 7

e^x at f''' x=0 yeah I do too thanks

Answer 8

have another one

Answer 9

what is it