Ask
your own question, for FREE!
Mathematics
18 Online
OpenStudy (anonymous):
Find the general potential function:
F=
phi= (blank) + c
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (amistre64):
or... you are integrating this up to the surface equation?
OpenStudy (amistre64):
df/dx = cos(z)
f = x + sin(z) +g(y)
like this?
OpenStudy (amistre64):
well; cos(z) would up to x cos(z) from df/dx i would think
OpenStudy (anonymous):
let me get a screen shot
OpenStudy (anonymous):
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (amistre64):
i dont know what they conservative means; but im pretty sure we are suiting it back up to a surface equation ....
OpenStudy (amistre64):
there are ways to test if the F is a gradient of not, but I dont recall them at the moment
OpenStudy (amistre64):
df/dx = cos(z) ; x + j(y) +x cos(z) +c
df/dy = 2y ; g(x) +y^2 + h(z) +c
df/dz = -x sin(z) ; g(x) +j(y) +x cos(z) +c
is my best interpretation
OpenStudy (amistre64):
looks to be able to derive from:
f(x,y,z) = x + y^2 +x cos(z) +c .... nope, that would have a 1+cos(z) for df/dx wouldnt it :)
OpenStudy (amistre64):
ax the g(x) and try it :)
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (amistre64):
f(x,y,z) = y^2 + x cos(z) +c
OpenStudy (anonymous):
awesome ! I check it and it was right thanks a million
OpenStudy (anonymous):
you cleared it up :)
OpenStudy (amistre64):
yay!! I cant wait till I actually learn this stuff lol
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!