Find the general potential function:
F=
or... you are integrating this up to the surface equation?
df/dx = cos(z) f = x + sin(z) +g(y) like this?
well; cos(z) would up to x cos(z) from df/dx i would think
let me get a screen shot
i dont know what they conservative means; but im pretty sure we are suiting it back up to a surface equation ....
there are ways to test if the F is a gradient of not, but I dont recall them at the moment
df/dx = cos(z) ; x + j(y) +x cos(z) +c df/dy = 2y ; g(x) +y^2 + h(z) +c df/dz = -x sin(z) ; g(x) +j(y) +x cos(z) +c is my best interpretation
looks to be able to derive from: f(x,y,z) = x + y^2 +x cos(z) +c .... nope, that would have a 1+cos(z) for df/dx wouldnt it :)
ax the g(x) and try it :)
f(x,y,z) = y^2 + x cos(z) +c
awesome ! I check it and it was right thanks a million
you cleared it up :)
yay!! I cant wait till I actually learn this stuff lol
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