Question

A boat at anchor is bobbing up and down in the sea. The vertical distance, y, in feet, between the sea floor and the boat is given as a function of time, t, in minutes, by y=18+2sin(2*pi*t) ft.
Find the vertical velocity, v, of the boat at time t.

Answer 1

v=?

Answer 2

the derivative of position is velocity

Answer 3

y'=4pi.cos(2pi.t)

Answer 4

2pi*cos(2pi*t) ;] thanks

Answer 5

dont forget the 2 that was hanging out there to begin with

Answer 6

2.2pi.cos(2pi.t)

Answer 7

haha, i typed the equation wrong. it was sin(2*pi*t). In that case you were right, again.

Answer 8

lol ..... thnx ;)