Question

Derivative of e^(lnx)^2

Answer 1

Use the chain rule twice.

Answer 2

how do u do it

Answer 3

derivative of e^u = e^u * du/dx

What is the u in this case?

Answer 4

would it be (lnx)^2

Answer 5

right. what is the derivative of u^2?

Answer 6

2u

Answer 7

right 2u * du/dx

Answer 8

2lnx * ??

Answer 9

its 1/x^2

Answer 10

just the 1/x, the square is on the "outside"

Answer 11

therefore its 2 over x

Answer 12

put it all together. e^ln x ^2 * 2ln x * 1/x and clean it up.

Answer 13

OK? Gotta go. Good luck with it.

Answer 14

it's e^U

Answer 15

\[=(2\log^2_{x} logx)/x\] I guess....

Answer 16

Mmmm.... not so sure. Try this:

we know d/dx(e^x) = e^x

So d/dx(e^(lnx)^2) = e^(lnx)^2 times d/dx(lnx)^2

= e^(lnx)^2 times 2lnx times d/dx(lnx)

= e^(lnx)^2 times 2lnx times (1/x)