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Mathematics 14 Online
OpenStudy (anonymous):

x^2+2y^2=2 x-y=9

OpenStudy (anonymous):

write second equation as x = y+9 and substitute into first equation

OpenStudy (anonymous):

get \[(y+9)^2+2y^2=2\]

OpenStudy (anonymous):

now multiply out and collect terms on the left \[y^2+18y+81+2y^2=2\] \[3y^2+18y+79=0\]

OpenStudy (anonymous):

now you have a quadratic equation. if you are lucky it factors

OpenStudy (anonymous):

can you helo me factor it i would rather not do the quadratic equation

OpenStudy (anonymous):

Since 79 is prime, it doesn't look promising.

OpenStudy (anonymous):

wanna helo me the the quadratic equation then

OpenStudy (anonymous):

\[x=(-18\pm\sqrt{(18)^{2}-4(3)(79)})/6\]

OpenStudy (anonymous):

That radical looks negative to me. So doesn't look like there's a real solution.

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