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OpenStudy (anonymous):
You can multiply both sides of the equation by 2x-5 (with the stipulation that x cannot be 5/2). That should give you something you can solve pretty quickly.
OpenStudy (anonymous):
u are in the university or school? because there are 2 ways of solving it :S
OpenStudy (anonymous):
college
OpenStudy (anonymous):
ok the u might have to pass the 4 to le left so it can be -4, the get de MCM
OpenStudy (anonymous):
u know the critic points?
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OpenStudy (anonymous):
i think it's more to do with multiplying both sides
so far i get, (2x+10)/(2x-5)=4 , so that divide (2x-5) both sides = 2x+10 = 6x + 10?
OpenStudy (anonymous):
4(2x-5) = 8x -20 not 6x + 10.
OpenStudy (anonymous):
So you will have
2x + 10 = 8x - 20
OpenStudy (anonymous):
so then 10+20 = 8x - 2x?
OpenStudy (anonymous):
which = 30 = 6x?
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OpenStudy (anonymous):
and then x = 30/6?
OpenStudy (anonymous):
its ok but i was taught that if u dont know if x is negative u cannot do that :S thats why i asked u
OpenStudy (anonymous):
that right so far pol?
OpenStudy (anonymous):
Looks reasonable yes.
OpenStudy (anonymous):
so then x = 5 (i think)
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OpenStudy (anonymous):
Indeed. And if you plug 5 back in for x in the original equation?