Question

3y[1-(y-3)]-2[3-y(y-4)] simplfy

Answer 1

Do the bits in ( )'s first and simplify there...

Answer 2

how do you distribute the 1- to the (y-3) :( ??

Answer 3

OK you you have 1 minus y minus minus 3 which is...?

Answer 4

y+4?

Answer 5

Good, now how about the other ( )?

Answer 6

It's -y not y

Answer 7

final answer : 5y^2 + 14y+24 ?

Answer 8

you can just "read" it--- plus1 minusy minusminus3

Answer 9

is my answer correct? im confused again

Answer 10

You are going a bit too fast, do it more slowly and remember minus minus is a plus...

Answer 11

so...your are saying that 3-y(y-4) = -y^2 -12 ?

Answer 12

the y(y-4) you should first and then plus3

Answer 13

Basically you want to get rid of those inside ( )'s before you do anything else, do you see what i mean?

Answer 14

noo i dont understand..
y(y-4)+3 ?

Answer 15

It doesn't say y(y-4) +3 it says -y(y-4) +3...

Answer 16

Expand -y(y-4) and what do you get?

Answer 17

-y^2-4

Answer 18

-y^2-4y

Answer 19

You seem to be getting stuck every time on minus minus, minus y times minus 4 equals PLUS 4y

Answer 20

SOO 3y (y-4) -2 (-y^2+4y) :D ?
nut there is the plus there for the second bracket go ?
3y (y-4) -2 (-y^2+4y)+3 ?

Answer 21

Write the original question with the ( )'s expanded as we discussed and be careful with the signs

Answer 22

3y^2-12y+2y^2-8y
5y^2-20y

Answer 23

3y[ put something here ] -2 [ and here ]

Answer 24

3y[ y-4] -2 [-y(y-4+3]

Answer 25

i give up..

Answer 26

Why do you put y-4?

Answer 27

that what you said to write

Answer 28

3y[ -y + 4 ] -2[ 3 - y^2 + 4y ] You need to understand this, then you can do the rest, OK

Answer 29

thamks sexy\

Answer 30

You're welcome:-)

Answer 31

where u live

Answer 32

final answer= y^2+4y-6

Answer 33

????

Answer 34

It's -y^2 not + y^2 (I live in Spain).

Answer 35

ok ty