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Mathematics 16 Online
OpenStudy (anonymous):

sqrt{x+4}+2=x

OpenStudy (anonymous):

subtract 2 from both sides and square both sides. you will end up with a quadratic equation. solve that for x

OpenStudy (anonymous):

can you show me how to set that up ?

OpenStudy (anonymous):

sqrt(x+4) = x-2 square both sides x+4 = (x-2)^2

OpenStudy (anonymous):

i got it down to x^2-5x=0

OpenStudy (anonymous):

explain some more please

OpenStudy (anonymous):

\[\sqrt{x+4}=x-2\] \[x+4=(x-2)^{2}\] \[x+4=x ^{2}-4x+4\] \[x^2-4x-x=0\] \[x ^{2}-5x=0\]

OpenStudy (anonymous):

x(x-5)=0 x=0 x=5

OpenStudy (anonymous):

actually 0 wouldn't work - put x=0 in your original equation... but x=5 is good

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