Question

solve 5x^2-x+4=0 by completing the square.

Answer 1

5x^2-x=-4
x^2-1/5*x=-4/5
x^2-1/5*x+(1/[2*5])^2=-4/5+(1/[2*5])^2
x^2-1/5*x+(1/10)^2=-4/5+(1/10)^2
(x-1/10)^2=-4/5+1/100
do u think u can finish it

Answer 2

(x-1/10)^2=-4/5*20/20+1/100
(x-1/10)^2=-80/100+1/100
(x-1/10)^2=-79/100

Answer 3

mome do you have any question
you just take the square root of both sides and then add 1/10 and you are done
you might be able to simplify and stuff
you can say sqrt{-1} is i

Answer 4

myininaya, I was confused because I thought you take half of the middle term (x) or 1.

Answer 5

\[\frac{5x^2-x+4}{5}=\frac{0}{5}\]

Answer 6

you do mome
1/2*1/5
and then don't forget to square after you take a half of the middle term

Answer 7

\[x^2-\frac{1}{5}x+\frac{4}{5}=0\]

Answer 8

\[\frac{\frac{1}{5}}{2}=\frac{1}{10}\]

Answer 9

\[(\frac{1}{10})^2=\frac{1}{100}\]

Answer 10

\[(x-\frac{1}{10})^2=-\frac{4}{5}+\frac{1}{100}\]can u solve from now?

Answer 11

still trying to understand it. California

Answer 12

let me know when u ready go next step

Answer 13

ready

Answer 14

frist step divi 5 get rid coefficient
second step take (1/5)/2 = 1/10
(x- 1/10 )^2
thrid step (1/10)^=1/100
move 4/5 to right hand side u get (-4/5 )+ 1/100

Answer 15

now get rid with square on the left , u need square root on the right hand side

Answer 16

\[x-\frac{1}{10}=\pm \sqrt{\frac{-80+1}{100}}\]

Answer 17

\[x-\frac{1}{10}=\pm \sqrt{\frac{-79}{100}}\]

Answer 18

\[x=\frac{1}{10}\pm\frac{\sqrt{-1}*\sqrt{79}}{10}\]

Answer 19

\[x=\frac{1}{10}\pm i \frac{\sqrt{79}}{10}\]

Answer 20

is your answer

Answer 21

?