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If sin A = 2/3 where 0° < A < 90°, what is the value of sin 2A
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41.81
sin2A=2sinAcosA sinA=2/3 we need to know what cosA is sinA=opp/hyp=2/3 (opp)^2+(adj)^2=(hyp)^2 2^2+(adj)^2=3^2 (adj)^2=9-4 adj=sqrt{3} cosA=adj/hyp=sqrt{3}/3
so sin2a=2*2/3*sqrt{3}/3=4sqrt{3}/9
answer given is actually 4sqrt{5} /9
dont know how to get it though
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oh strive do you see i subtract wrong above
see that 9-4 i put 3 for some reason its suppose to be 5
strive?
ohhh gotcha
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