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Physics 14 Online
OpenStudy (anonymous):

An ostrich is running at a speed of 17.0 m/s in a direction of 68.0 degrees north of west. what is the magnitude of the ostrich velocity component that is directed (a) due north and (b) due west?

OpenStudy (anonymous):

speed is 17.0 m/s in a direction of 68.0 degrees north of west then, the west component can be calculated using, cos68, ie: adjuscent side(Velocity due west)/hypotenuse(17) cos68=Velocity due west/17 Velocity due west=17cos68=6.368m/s along west same way is used to find Velocity due north(angle will become (90-68)degrees if you are using cos Velocity due north=17cos(90-68)=15.762 m/s due north

OpenStudy (anonymous):

Above user is correct. West can be treated as the positive x axis, and north as the positive y. Then just use trig.

OpenStudy (anonymous):

careful danny - if West is the positive x, North would be the negative y - West would have to be negative x for North to be positive y

OpenStudy (anonymous):

west=17cos68 north=17sin68 now Stan is it compulsary that north should negative y if west is positive x. cant we rotate the axis and make west positive y and north positive x

OpenStudy (anonymous):

of course george7, but you can't rotate the axis to make west positive x and north positive y

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