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Mathematics 21 Online
OpenStudy (anonymous):

625^x=3125

OpenStudy (anonymous):

\[x=\frac{\ln(3125)}{\ln(625)}\]

OpenStudy (anonymous):

you solve \[b^x=A\] for x in one step via \[x=\frac{\ln(A)}{\ln(b)}\]

OpenStudy (anonymous):

if 3125 is an integer power of x then you can guess perhaps

OpenStudy (anonymous):

i mean if 3125 is an integer power of 625

OpenStudy (anonymous):

but it is not

OpenStudy (anonymous):

ok so now what?

OpenStudy (anonymous):

625 = 5^4, 3125 = 5^5. Take log(5) of both sides to get x log(5)(5^4) = log(5)(5^4) 4x = 4 x = 1.

OpenStudy (anonymous):

oops x log(5)(5^4) = log(5)(5^5) 4x = 5 x = 5/4

OpenStudy (anonymous):

too much work. whip out mr calculator and type in \[\frac{\ln(3125)}{\ln(625)}\] you will get \[\frac{5}{4}\]

OpenStudy (anonymous):

although of course abtrhearn is right. but if you recognize that \[625=5^4\] and \[3125=5^5\] you do not need logs. just write \[5^{4x}=5^5\] so \[4x=5\] and \[x=\frac{5}{4}\]

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