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Simplify: i(sqrt-98) -( sqrt98)
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\[i\sqrt{-98}-\sqrt{98}\]?
yes
-2sqrt(98)
\[\sqrt{-98}=\sqrt{98}i\] giving \[i^2\sqrt{98}-\sqrt{98}=-\sqrt{98}-\sqrt{98}=-2\sqrt{98}\]
not done yet however!
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11i
\[98=2\times 49\] so \[\sqrt{98}=7\sqrt{2}\]
therefore you "final answer is \[-14\sqrt{2}\]
11i?
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