Question

What is the equation of a circle whose center is at the origin and whose radius is 16?

Answer 1

x^2 + y^2 = r^2; is the standard format

since the center is already at origin; id go with x^2+y^2=sqrt(16), or simply:

x^2 + y^2 = 4

Answer 2

16*16 = 256 tho; not 4 ..... ack

Answer 3

\[x^2 + y^2 = 256\]

Answer 4

typical trick question. make the radius a perfect square see if you take the square root!

Answer 5

hook line and sinker i fall for these

Answer 6

oops i forgot the squared x^2 + y^2 =4

Answer 7

amistre is right

Answer 8

lol ... yep

Answer 9

@safiah don't fall for the trap
it is
\[(x-h)^2+(y-k)^2=r^2\]

Answer 10

amsitre has it

Answer 11

at least eventually im right ;)