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Mathematics 19 Online
OpenStudy (anonymous):

What are the possible number of positive, negative, and complex zeros of f(x) = x6 + x5+ x4 + 4x3 – 12x2 + 12 ? Answer Positive: 2 or 0; Negative: 4, 2, or 0; Complex: 6, 4, 2, or 0 Positive: 4, 2, or 0; Negative: 2 or 0; Complex: 4, 2, or 0 Positive: 2 or 0; Negative: 2 or 0; Complex: 4, 2, or 0 Positive: 2 or 0; Negative: 0; Complex: 6, 4, 2, or 0

OpenStudy (anonymous):

just see which option satisfies the equation

OpenStudy (anonymous):

Which one do you think it is?

myininaya (myininaya):

+ =2 or 0 - =4 or 2 or 0 complex= 4 or 2 or 6or 0

OpenStudy (anonymous):

oh. the question asks how many positive negative and imaginary roots there are.

myininaya (myininaya):

the first choice

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