What are the possible number of positive, negative, and complex zeros of f(x) = 3x4 – 5x3 – x2 – 8x + 4 ? Answer Positive: 2; Negative: 2; Complex: 4 or 2 or 0 Positive: 3 or 1; Negative: 1; Complex: 2 or 0 Positive: 1; Negative: 3 or 1; Complex: 2 or 0 Positive: 2 or 0; Negative: 2 or 0; Complex: 4 or 2 or 0
im guessing the last one ....
2 sign changes in + gives us either 2 or 0 roots
product of roots is +4, so positive 0 or 2, neghative 2 or 0. Complex roots always in pairs, so 0, 2 or 4 are the complex possibilities, so yes amistre64 is correct
Ooops! Why not 4 positives or 4 negatives?
4 positives not possible because some of the coefficients are negative
4 negatives not possible because sum of roots =-(-5)
Here are some general theorems about polynomials which might come in handy: http://home.windstream.net/okrebs/page26.html
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