Question

Solve:
p2 + 20p + 200 = 0

i got as far as -20+- sqrt -400 / 2

Answer 1

\[p=(-b\pm\sqrt{b^2-4ac})/2a\]a=1, b=20, c=200
\[p=(-20\pm\sqrt{400-4(1)(200)})/2\]
The discriminant looks negative to me. No real solution...

Answer 2

what about using i ? to make it postive can i do that ?

Answer 3

complex solution is \[-10\pm 10i\]

Answer 4

Yes, you can. Wasn't sure if you were using complex roots or not.

Just calculate the radical and pull the negative out as i and finish as normal.

Answer 5

thanks :)

Answer 6

no problem :)