*NEED HELP * A softball is thrown up into the air. The ball's height in feet is modeled by the equation h(t) = -16t2 + 32t + 5. h = height t = time in seconds Find the maximum height of the ball. a) 8.3 feet b) 7.6 feet c) 13.9 feet d) 12.2 feet
define "help" please; is it: a) give me the answer b) teach me how to get the answer c) other
a)
:)
This is like the basketball question that amistre answered for you. Review his answer and solve tour question
you can graph this on wolframalpha.com and be able to see the answer much clearly :)
-32/2(-16) = 1 as the vertex
and at 1 we get: -16 + 32 + 5 as the answer
okay but I need one of the choices to be the answers
youre choices dont match up with the answer :/
is there a typo in the equation?
nope
the max height of the ball by this equaton is 21 feet; so im inclined to believe otherwise
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