Question

Calculate the first four terms of the following sequence, starting with n=1.

Cn=5+(5/2)+(5/3)+(5/4).......(5/n).??? need some help

Answer 1

hold that :)

Answer 2

A{1} = 5/1
A{2} = 5 + 5/2
A{3} = 5 + 5/2 + 5/3
A{4} = 5 + 5/2 + 5/3 + 5/4

thats better

Answer 3

5, 7.5, 9.1666.... , 10.416666......

Answer 4

so for a problem like that you just take waht n = and whatever the last term is and go that far out with the terms:?

Answer 5

like this one ... Calculate the first four terms of the following sequence, starting with n=1

b1=4 b2=2 bn=bn−1+4bn−2

Answer 6

it depends on how they define the progression;

Answer 7

what 'equation' do they give you to compute the terms by?

Answer 8

b{1}=4; b{2}=2;

b{n}=b{n−1} +4 b{n−2} ; thats easier to read

Answer 9

its b sub (n-1) + 4b sub(n-2)

Answer 10

b{1} = 1
b{2} = 2
b{3} = 2 +4(1) = 6
b{4} = 6 +4(2) = 14
b{5} = 14 +4(6) = 38

Answer 11

not correct... the formula isnt b *(n-1) + 4 * b(n-2)...The (n-1) is a sub score to b same as (n-2)