Question

Write the standard form of the equation of the circle with endpoints of a diameter at the points of (5,8) and (-9,11)

Answer 1

add the points and divide by 2 to find the center

Answer 2

( 5, 8 )
+(-9,11)
----------
(-4,19); /2 to get (-2, 19/2)

alot of it is just now: \((x+2)^2+(y-(19/2))^2 = r^2\)

Answer 3

to get r; subtract the center from an endpoint

( 5,8 )
-(-2,19/2)

( 5,16/2)
-(-2,19/2)
-----------
7, -3/2 ; now we squre them and add them

(7)^2 + (-3/2)^2 = r^2

Answer 4

I'm getting (x+2)\[(x+2)^{2}+ (y-19/2)^{2}=205/2\]

Answer 5

but not sure that is right

Answer 6

it should come out to 51' 1/4 ; which equals 205/4

Answer 7

ugh, so close

Answer 8

:)

Answer 9

thanks