Write the standard form of the equation of the circle with endpoints of a diameter at the points of (5,8) and (-9,11)

Question

amistre64 · Answer

add the points and divide by 2 to find the center

amistre64 · Answer

(  5, 8 )
+(-9,11)
----------
  (-4,19); /2  to get (-2, 19/2)

alot of it is just now:  $(x+2)^2+(y-(19/2))^2 = r^2$

amistre64 · Answer

to get r; subtract the center from an endpoint

  (  5,8    )
-(-2,19/2)

  ( 5,16/2)
-(-2,19/2)
-----------
    7, -3/2  ; now we squre them and add them

(7)^2 + (-3/2)^2 = r^2

anonymous · Answer

I'm getting (x+2)$$(x+2)^{2}+ (y-19/2)^{2}=205/2$$

anonymous · Answer

but not sure that is right

amistre64 · Answer

it should come out to 51' 1/4 ; which equals 205/4

anonymous · Answer

ugh, so close

amistre64 · Answer

:)

anonymous · Answer

thanks