A uniform meter rod of weigh 2N is pivoted at the 60cm mark. A weight of 4N is hung from one end causing the rule to rotate about the pivot. What is the resultant torque?
A) 0N
B) 1.4N
C) 1.6N
D) 1.8N
E) None of the above.

[Please explain fully]

Question

A uniform meter rod of weigh 2N is pivoted at the 60cm mark. A weight of 4N is hung from one end causing the rule to rotate about the pivot. What is the resultant torque? 
A) 0N
B) 1.4N
C) 1.6N
D) 1.8N
E) None of the above.

[Please explain fully]

anonymous · Answer

for the rod to rotate the 4N force should be exerted at the end which is maximum from the pivot...
so it will be ... 
4*0.6  + 2*0.1 = 2.6N
so answer must be E